20-14y+2y^2=0

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Solution for 20-14y+2y^2=0 equation: 



20-14y+2y^2=0

a = 2; b = -14; c = +20;
Δ = b2-4ac
Δ = -142-4·2·20
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-6}{2*2}=\frac{8}{4}
=2
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+6}{2*2}=\frac{20}{4}
=5
$

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